Talk:Parsec
Appearance
This is the talk page for discussing improvements to the Parsec article. This is not a forum for general discussion of the article's subject. |
Article policies
|
Find sources: Google (books · news · scholar · free images · WP refs) · FENS · JSTOR · TWL |
Archives: 1Auto-archiving period: 60 days ![]() |
![]() | This ![]() It is of interest to the following WikiProjects: | |||||||||||||||||
|
Precision
[edit]“ | It is therefore 360×60×60/2π AU = 206,264.806 247 AU = 3.085 677 581 31×1016 m = ~3.26 light-years. | ” |
I was trying to correct the precision of this calculation, but I think it is only a (close) approximation anyway, using the fact that tan(θ)~=θ for small θ. So, I have trimmed the number of significant digits.
Ray Spalding 17:49, 19 Mar 2004 (UTC)
- The computation offered here is not immediately clear. I think the use of the approximation tan(θ) ~= θ for small θ is acceptable here, but we should either mention this as a whole, or leave out any form of computation. I prefer the latter, that is, to just state that a parsec is approximately ... km / miles / etc . without any calculations.
- Maurice Termeer 08:21, 27 Mar 2006 (UTC)
4,000,000,000,000,000 kilometers?
[edit]4,000,000,000,000,000 kilometers doesn't fit here, does it?
3.08567758 E+16 m = 4,000,000,000,000,000 kilometers is not correct. First of all there are two too many zeros. Secondly, if 1 km = 1000 m then the result would start with a 3, not a 4.
3.08567758 E+16 m = 30856775800000000 m = 30856775800000 km
Or am I missing something here???
Midavalo 8 March 2006
Categories:
- B-Class vital articles
- Wikipedia level-4 vital articles
- Wikipedia vital articles in Physical sciences
- B-Class level-4 vital articles
- Wikipedia level-4 vital articles in Physical sciences
- B-Class vital articles in Physical sciences
- B-Class Astronomy articles
- Top-importance Astronomy articles
- B-Class Astronomy articles of Top-importance
- B-Class Measurement articles